12^x-4=4^2-x

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Solution for 12^x-4=4^2-x equation:



12^x-4=4^2-x
We move all terms to the left:
12^x-4-(4^2-x)=0
We get rid of parentheses
12^x+x-4-4^2=0
We add all the numbers together, and all the variables
x+12^x-20=0
We move all terms containing x to the left, all other terms to the right
x+12^x=20

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